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1.4x^2+28x+13=0
a = 1.4; b = 28; c = +13;
Δ = b2-4ac
Δ = 282-4·1.4·13
Δ = 711.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-\sqrt{711.2}}{2*1.4}=\frac{-28-\sqrt{711.2}}{2.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+\sqrt{711.2}}{2*1.4}=\frac{-28+\sqrt{711.2}}{2.8} $
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